Base | Representation |
---|---|
bin | 10000010011011110111… |
… | …010010011101111101111 |
3 | 10222010000210012120110202 |
4 | 100103132322103233233 |
5 | 121324120404333033 |
6 | 2214415151424115 |
7 | 143643222055145 |
oct | 20233672235757 |
9 | 3863023176422 |
10 | 1120431324143 |
11 | 3a219930024a |
12 | 16119222503b |
13 | 8186b9410a1 |
14 | 3c32cb89595 |
15 | 1e22951b8e8 |
hex | 104dee93bef |
1120431324143 has 2 divisors, whose sum is σ = 1120431324144. Its totient is φ = 1120431324142.
The previous prime is 1120431324127. The next prime is 1120431324151. The reversal of 1120431324143 is 3414231340211.
It is a strong prime.
It is an emirp because it is prime and its reverse (3414231340211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1120431324143 - 24 = 1120431324127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120431324343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560215662071 + 560215662072.
It is an arithmetic number, because the mean of its divisors is an integer number (560215662072).
Almost surely, 21120431324143 is an apocalyptic number.
1120431324143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120431324143 is an equidigital number, since it uses as much as digits as its factorization.
1120431324143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1120431324143 its reverse (3414231340211), we get a palindrome (4534662664354).
The spelling of 1120431324143 in words is "one trillion, one hundred twenty billion, four hundred thirty-one million, three hundred twenty-four thousand, one hundred forty-three".
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