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112054614423133 is a prime number
BaseRepresentation
bin11001011110100110111111…
…011111001111011001011101
3112200202022112202001210020111
4121132212333133033121131
5104141400322243020013
61034153102413250021
732413451543124214
oct3136467737173135
9480668482053214
10112054614423133
1132782105647468
1210698b27793911
134a6a9215a2725
141d95687cd407b
15ce4be722673d
hex65e9bf7cf65d

112054614423133 has 2 divisors, whose sum is σ = 112054614423134. Its totient is φ = 112054614423132.

The previous prime is 112054614423107. The next prime is 112054614423149. The reversal of 112054614423133 is 331324416450211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111911580695929 + 143033727204 = 10578827^2 + 378198^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112054614423133 is a prime.

It is a super-2 number, since 2×1120546144231332 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112054614423733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56027307211566 + 56027307211567.

It is an arithmetic number, because the mean of its divisors is an integer number (56027307211567).

Almost surely, 2112054614423133 is an apocalyptic number.

It is an amenable number.

112054614423133 is a deficient number, since it is larger than the sum of its proper divisors (1).

112054614423133 is an equidigital number, since it uses as much as digits as its factorization.

112054614423133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 40.

The spelling of 112054614423133 in words is "one hundred twelve trillion, fifty-four billion, six hundred fourteen million, four hundred twenty-three thousand, one hundred thirty-three".