Base | Representation |
---|---|
bin | 110100001100110101… |
… | …1111111001011101011 |
3 | 101201100110010200012001 |
4 | 1220121223333023223 |
5 | 3314040112023313 |
6 | 123255330231431 |
7 | 11045642136202 |
oct | 1503153771353 |
9 | 351313120161 |
10 | 112100111083 |
11 | 435a5654704 |
12 | 19886125577 |
13 | a75662649c |
14 | 55d609c239 |
15 | 2db1682add |
hex | 1a19aff2eb |
112100111083 has 2 divisors, whose sum is σ = 112100111084. Its totient is φ = 112100111082.
The previous prime is 112100110961. The next prime is 112100111107. The reversal of 112100111083 is 380111001211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112100111083 - 217 = 112099980011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112100111083.
It is not a weakly prime, because it can be changed into another prime (112100111983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050055541 + 56050055542.
It is an arithmetic number, because the mean of its divisors is an integer number (56050055542).
Almost surely, 2112100111083 is an apocalyptic number.
112100111083 is a deficient number, since it is larger than the sum of its proper divisors (1).
112100111083 is an equidigital number, since it uses as much as digits as its factorization.
112100111083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 112100111083 its reverse (380111001211), we get a palindrome (492211112294).
The spelling of 112100111083 in words is "one hundred twelve billion, one hundred million, one hundred eleven thousand, eighty-three".
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