112100122101113 has 2 divisors, whose sum is σ = 112100122101114. Its totient is φ = 112100122101112.

The previous prime is 112100122101001. The next prime is 112100122101161. The reversal of 112100122101113 is 311101221001211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84087946322704 + 28012175778409 = 9169948^2 + 5292653^2 .

It is an emirp because it is prime and its reverse (311101221001211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112100122101113 - 2¹² = 112100122097017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112100122101091 and 112100122101100.

It is not a weakly prime, because it can be changed into another prime (112100122101193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050061050556 + 56050061050557.

It is an arithmetic number, because the mean of its divisors is an integer number (56050061050557).

Almost surely, 2^{112100122101113} is an apocalyptic number.

It is an amenable number.

112100122101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112100122101113 is an equidigital number, since it uses as much as digits as its factorization.

112100122101113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 112100122101113 its reverse (311101221001211), we get a palindrome (423201343102324).

The spelling of 112100122101113 in words is "one hundred twelve trillion, one hundred billion, one hundred twenty-two million, one hundred one thousand, one hundred thirteen".