Base | Representation |
---|---|
bin | 10000010100000000111… |
… | …111100000101111011001 |
3 | 10222011111122010110220212 |
4 | 100110000333200233121 |
5 | 121331303244112213 |
6 | 2214552015100505 |
7 | 143663334150260 |
oct | 20240077405731 |
9 | 3864448113825 |
10 | 1121003113433 |
11 | 3a246203aa85 |
12 | 161311811735 |
13 | 81930240248 |
14 | 3c384aab5d7 |
15 | 1e25e8159a8 |
hex | 10500fe0bd9 |
1121003113433 has 8 divisors (see below), whose sum is σ = 1281874767360. Its totient is φ = 960313547520.
The previous prime is 1121003113361. The next prime is 1121003113453. The reversal of 1121003113433 is 3343113001211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1121003113433 - 236 = 1052283636697 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1121003113399 and 1121003113408.
It is not an unprimeable number, because it can be changed into a prime (1121003113453) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45508808 + ... + 45533433.
It is an arithmetic number, because the mean of its divisors is an integer number (160234345920).
Almost surely, 21121003113433 is an apocalyptic number.
It is an amenable number.
1121003113433 is a deficient number, since it is larger than the sum of its proper divisors (160871653927).
1121003113433 is an equidigital number, since it uses as much as digits as its factorization.
1121003113433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91044007.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1121003113433 its reverse (3343113001211), we get a palindrome (4464116114644).
The spelling of 1121003113433 in words is "one trillion, one hundred twenty-one billion, three million, one hundred thirteen thousand, four hundred thirty-three".
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