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112100433001 = 595773292907
BaseRepresentation
bin110100001100110110…
…1001101110001101001
3101201100110202000202221
41220121231031301221
53314040202324001
6123255341154041
711045644646554
oct1503155156151
9351313660687
10112100433001
11435a5854557
121988625b921
13a756709b7b
1455d614369b
152db16e81a1
hex1a19b4dc69

112100433001 has 8 divisors (see below), whose sum is σ = 114198049440. Its totient is φ = 110009403648.

The previous prime is 112100432933. The next prime is 112100433019. The reversal of 112100433001 is 100334001211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112100433001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (112100433061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1612411 + ... + 1680496.

It is an arithmetic number, because the mean of its divisors is an integer number (14274756180).

Almost surely, 2112100433001 is an apocalyptic number.

It is an amenable number.

112100433001 is a deficient number, since it is larger than the sum of its proper divisors (2097616439).

112100433001 is an equidigital number, since it uses as much as digits as its factorization.

112100433001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3293543.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 112100433001 its reverse (100334001211), we get a palindrome (212434434212).

The spelling of 112100433001 in words is "one hundred twelve billion, one hundred million, four hundred thirty-three thousand, one".

Divisors: 1 59 577 34043 3292907 194281513 1900007339 112100433001