Base | Representation |
---|---|
bin | 100001011010001… |
… | …0010101110011011 |
3 | 2220010100221000002 |
4 | 1002310102232123 |
5 | 4243434120233 |
6 | 303123003215 |
7 | 36531244346 |
oct | 10264225633 |
9 | 2803327002 |
10 | 1121004443 |
11 | 525861259 |
12 | 27350950b |
13 | 14b326350 |
14 | a8c4945d |
15 | 686346e8 |
hex | 42d12b9b |
1121004443 has 4 divisors (see below), whose sum is σ = 1207235568. Its totient is φ = 1034773320.
The previous prime is 1121004421. The next prime is 1121004481. The reversal of 1121004443 is 3444001211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1121004443 - 28 = 1121004187 is a prime.
It is a super-2 number, since 2×11210044432 = 2513301922451480498, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1121004043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43115543 + ... + 43115568.
It is an arithmetic number, because the mean of its divisors is an integer number (301808892).
Almost surely, 21121004443 is an apocalyptic number.
1121004443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1121004443 is a deficient number, since it is larger than the sum of its proper divisors (86231125).
1121004443 is an equidigital number, since it uses as much as digits as its factorization.
1121004443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86231124.
The product of its (nonzero) digits is 384, while the sum is 20.
The square root of 1121004443 is about 33481.4044358955. The cubic root of 1121004443 is about 1038.8091778691.
Adding to 1121004443 its reverse (3444001211), we get a palindrome (4565005654).
The spelling of 1121004443 in words is "one billion, one hundred twenty-one million, four thousand, four hundred forty-three".
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