Base | Representation |
---|---|
bin | 10100111000010110… |
… | …01000110100001111 |
3 | 1001221020210002020021 |
4 | 22130023020310033 |
5 | 140424241144413 |
6 | 5052211203011 |
7 | 544540164145 |
oct | 123413106417 |
9 | 31836702207 |
10 | 11210099983 |
11 | 483289a045 |
12 | 220a2a6467 |
13 | 1098609b74 |
14 | 784b61595 |
15 | 45924118d |
hex | 29c2c8d0f |
11210099983 has 2 divisors, whose sum is σ = 11210099984. Its totient is φ = 11210099982.
The previous prime is 11210099969. The next prime is 11210100007. The reversal of 11210099983 is 38999001211.
It is a weak prime.
It is an emirp because it is prime and its reverse (38999001211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11210099983 - 29 = 11210099471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11210099903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605049991 + 5605049992.
It is an arithmetic number, because the mean of its divisors is an integer number (5605049992).
Almost surely, 211210099983 is an apocalyptic number.
11210099983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210099983 is an equidigital number, since it uses as much as digits as its factorization.
11210099983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 43.
The spelling of 11210099983 in words is "eleven billion, two hundred ten million, ninety-nine thousand, nine hundred eighty-three".
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