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112101012120157 is a prime number
BaseRepresentation
bin11001011111010010001101…
…000000011010001001011101
3112200220202022021112000011121
4121133102031000122021131
5104143130333100321112
61034230254413050541
732420013404054014
oct3137221500321135
9480822267460147
10112101012120157
113279a854968a15
12106a5b16186a51
134a72106c37018
141d97a0a035a7b
15ce6010702407
hex65f48d01a25d

112101012120157 has 2 divisors, whose sum is σ = 112101012120158. Its totient is φ = 112101012120156.

The previous prime is 112101012120151. The next prime is 112101012120239. The reversal of 112101012120157 is 751021210101211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83105576483076 + 28995435637081 = 9116226^2 + 5384741^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112101012120157 is a prime.

It is a super-2 number, since 2×1121010121201572 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112101012120151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050506060078 + 56050506060079.

It is an arithmetic number, because the mean of its divisors is an integer number (56050506060079).

Almost surely, 2112101012120157 is an apocalyptic number.

It is an amenable number.

112101012120157 is a deficient number, since it is larger than the sum of its proper divisors (1).

112101012120157 is an equidigital number, since it uses as much as digits as its factorization.

112101012120157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 280, while the sum is 25.

Adding to 112101012120157 its reverse (751021210101211), we get a palindrome (863122222221368).

The spelling of 112101012120157 in words is "one hundred twelve trillion, one hundred one billion, twelve million, one hundred twenty thousand, one hundred fifty-seven".