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112101300132229 is a prime number
BaseRepresentation
bin11001011111010010011110…
…001011000101100110000101
3112200220210001100110112110101
4121133102132023011212011
5104143131430313212404
61034230343142124101
732420023502114242
oct3137223613054605
9480823040415411
10112101300132229
113279a9924a4721
12106a5b96720631
134a721517c8475
141d97a363a85c9
15ce602ab442a4
hex65f49e2c5985

112101300132229 has 2 divisors, whose sum is σ = 112101300132230. Its totient is φ = 112101300132228.

The previous prime is 112101300132221. The next prime is 112101300132277. The reversal of 112101300132229 is 922231003101211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111460764020004 + 640536112225 = 10557498^2 + 800335^2 .

It is a cyclic number.

It is not a de Polignac number, because 112101300132229 - 23 = 112101300132221 is a prime.

It is a super-2 number, since 2×1121013001322292 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112101300132197 and 112101300132206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112101300132221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050650066114 + 56050650066115.

It is an arithmetic number, because the mean of its divisors is an integer number (56050650066115).

Almost surely, 2112101300132229 is an apocalyptic number.

It is an amenable number.

112101300132229 is a deficient number, since it is larger than the sum of its proper divisors (1).

112101300132229 is an equidigital number, since it uses as much as digits as its factorization.

112101300132229 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 112101300132229 in words is "one hundred twelve trillion, one hundred one billion, three hundred million, one hundred thirty-two thousand, two hundred twenty-nine".