Base | Representation |
---|---|
bin | 1010001100100001010000… |
… | …0011111100100001010111 |
3 | 1110200200111012100002112111 |
4 | 2203020110003330201113 |
5 | 2432131443003034312 |
6 | 35501521221131451 |
7 | 2234624144114122 |
oct | 243102403744127 |
9 | 43620435302474 |
10 | 11210201221207 |
11 | 363224638163a |
12 | 1310741859b87 |
13 | 63416b0247a1 |
14 | 2aa8103d93b9 |
15 | 14690a4d78a7 |
hex | a32140fc857 |
11210201221207 has 2 divisors, whose sum is σ = 11210201221208. Its totient is φ = 11210201221206.
The previous prime is 11210201221189. The next prime is 11210201221213. The reversal of 11210201221207 is 70212210201211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11210201221207 - 223 = 11210192832599 is a prime.
It is a super-2 number, since 2×112102012212072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11210201221007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605100610603 + 5605100610604.
It is an arithmetic number, because the mean of its divisors is an integer number (5605100610604).
Almost surely, 211210201221207 is an apocalyptic number.
11210201221207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210201221207 is an equidigital number, since it uses as much as digits as its factorization.
11210201221207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 11210201221207 its reverse (70212210201211), we get a palindrome (81422411422418).
The spelling of 11210201221207 in words is "eleven trillion, two hundred ten billion, two hundred one million, two hundred twenty-one thousand, two hundred seven".
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