Base | Representation |
---|---|
bin | 1010001100100001010010… |
… | …1001101000110110101111 |
3 | 1110200200111212221002121111 |
4 | 2203020110221220312233 |
5 | 2432132003020232002 |
6 | 35501522213012451 |
7 | 2234624324106352 |
oct | 243102451506657 |
9 | 43620455832544 |
10 | 11210211102127 |
11 | 3632250a10294 |
12 | 1310745024127 |
13 | 6341700a409b |
14 | 2aa81184c299 |
15 | 14690b2da3d7 |
hex | a3214a68daf |
11210211102127 has 2 divisors, whose sum is σ = 11210211102128. Its totient is φ = 11210211102126.
The previous prime is 11210211102091. The next prime is 11210211102197. The reversal of 11210211102127 is 72120111201211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11210211102127 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11210211102098 and 11210211102107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11210211102197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605105551063 + 5605105551064.
It is an arithmetic number, because the mean of its divisors is an integer number (5605105551064).
Almost surely, 211210211102127 is an apocalyptic number.
11210211102127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210211102127 is an equidigital number, since it uses as much as digits as its factorization.
11210211102127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 11210211102127 its reverse (72120111201211), we get a palindrome (83330322303338).
The spelling of 11210211102127 in words is "eleven trillion, two hundred ten billion, two hundred eleven million, one hundred two thousand, one hundred twenty-seven".
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