Base | Representation |
---|---|
bin | 10100111000010111… |
… | …00100011111101001 |
3 | 1001221020222211202011 |
4 | 22130023210133221 |
5 | 140424303311403 |
6 | 5052213435521 |
7 | 544541145523 |
oct | 123413443751 |
9 | 31836884664 |
10 | 11210213353 |
11 | 4832967239 |
12 | 220a33bba1 |
13 | 1098649651 |
14 | 784b90a13 |
15 | 459264a6d |
hex | 29c2e47e9 |
11210213353 has 2 divisors, whose sum is σ = 11210213354. Its totient is φ = 11210213352.
The previous prime is 11210213323. The next prime is 11210213383. The reversal of 11210213353 is 35331201211.
It is a balanced prime because it is at equal distance from previous prime (11210213323) and next prime (11210213383).
It can be written as a sum of positive squares in only one way, i.e., 10627135744 + 583077609 = 103088^2 + 24147^2 .
It is an emirp because it is prime and its reverse (35331201211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11210213353 is a prime.
It is not a weakly prime, because it can be changed into another prime (11210213323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605106676 + 5605106677.
It is an arithmetic number, because the mean of its divisors is an integer number (5605106677).
Almost surely, 211210213353 is an apocalyptic number.
It is an amenable number.
11210213353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210213353 is an equidigital number, since it uses as much as digits as its factorization.
11210213353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 11210213353 its reverse (35331201211), we get a palindrome (46541414564).
The spelling of 11210213353 in words is "eleven billion, two hundred ten million, two hundred thirteen thousand, three hundred fifty-three".
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