Base | Representation |
---|---|
bin | 11001011111010011010100… |
… | …011110100111010110101011 |
3 | 112200220212101211211122011111 |
4 | 121133103110132213112223 |
5 | 104143140312033032112 |
6 | 1034231013410011151 |
7 | 32420055204205405 |
oct | 3137232436472653 |
9 | 480825354748144 |
10 | 112102211220907 |
11 | 327a030a810076 |
12 | 106a61ab876ab7 |
13 | 4a722684a50ab |
14 | 1d97ac13adb75 |
15 | ce6080b115a7 |
hex | 65f4d47a75ab |
112102211220907 has 2 divisors, whose sum is σ = 112102211220908. Its totient is φ = 112102211220906.
The previous prime is 112102211220877. The next prime is 112102211221061. The reversal of 112102211220907 is 709022112201211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112102211220907 - 211 = 112102211218859 is a prime.
It is a super-3 number, since 3×1121022112209073 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (112102211220007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051105610453 + 56051105610454.
It is an arithmetic number, because the mean of its divisors is an integer number (56051105610454).
Almost surely, 2112102211220907 is an apocalyptic number.
112102211220907 is a deficient number, since it is larger than the sum of its proper divisors (1).
112102211220907 is an equidigital number, since it uses as much as digits as its factorization.
112102211220907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 31.
The spelling of 112102211220907 in words is "one hundred twelve trillion, one hundred two billion, two hundred eleven million, two hundred twenty thousand, nine hundred seven".
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