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1121031411131 = 1455777009783
BaseRepresentation
bin10000010100000010101…
…011011101010110111011
310222011120121101011001202
4100110002223131112323
5121331333020124011
62214554505404415
7143664126525662
oct20240253352673
93864517334052
101121031411131
113a2477008505
1216131b19970b
138193606a448
143c388755dd9
151e26205523b
hex10502add5bb

1121031411131 has 4 divisors (see below), whose sum is σ = 1121108435472. Its totient is φ = 1120954386792.

The previous prime is 1121031411121. The next prime is 1121031411173. The reversal of 1121031411131 is 1311141301211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1121031411131 is a prime.

It is a super-2 number, since 2×11210314111312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1121031411121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38490335 + ... + 38519448.

It is an arithmetic number, because the mean of its divisors is an integer number (280277108868).

Almost surely, 21121031411131 is an apocalyptic number.

1121031411131 is a deficient number, since it is larger than the sum of its proper divisors (77024341).

1121031411131 is an equidigital number, since it uses as much as digits as its factorization.

1121031411131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77024340.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 1121031411131 its reverse (1311141301211), we get a palindrome (2432172712342).

The spelling of 1121031411131 in words is "one trillion, one hundred twenty-one billion, thirty-one million, four hundred eleven thousand, one hundred thirty-one".

Divisors: 1 14557 77009783 1121031411131