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1121032012330 = 25112103201233
BaseRepresentation
bin10000010100000010101…
…101110000001000101010
310222011120122111200202101
4100110002231300020222
5121331333143343310
62214554530324014
7143664134611516
oct20240255601052
93864518450671
101121032012330
113a247738916a
1216131b42960a
138193621ac99
143c388871146
151e26212343a
hex10502b7022a

1121032012330 has 8 divisors (see below), whose sum is σ = 2017857622212. Its totient is φ = 448412804928.

The previous prime is 1121032012327. The next prime is 1121032012337. The reversal of 1121032012330 is 332102301211.

It can be written as a sum of positive squares in 2 ways, for example, as 1116443711161 + 4588301169 = 1056619^2 + 67737^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1121032012298 and 1121032012307.

It is not an unprimeable number, because it can be changed into a prime (1121032012337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56051600607 + ... + 56051600626.

Almost surely, 21121032012330 is an apocalyptic number.

1121032012330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1121032012330 is a deficient number, since it is larger than the sum of its proper divisors (896825609882).

1121032012330 is a wasteful number, since it uses less digits than its factorization.

1121032012330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112103201240.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1121032012330 its reverse (332102301211), we get a palindrome (1453134313541).

The spelling of 1121032012330 in words is "one trillion, one hundred twenty-one billion, thirty-two million, twelve thousand, three hundred thirty".

Divisors: 1 2 5 10 112103201233 224206402466 560516006165 1121032012330