11210331313081 has 2 divisors, whose sum is σ = 11210331313082. Its totient is φ = 11210331313080.

The previous prime is 11210331313063. The next prime is 11210331313099. The reversal of 11210331313081 is 18031313301211.

11210331313081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (11210331313063) and next prime (11210331313099).

It can be written as a sum of positive squares in only one way, i.e., 7862836605625 + 3347494707456 = 2804075^2 + 1829616^2 .

It is a cyclic number.

It is not a de Polignac number, because 11210331313081 - 2³¹ = 11208183829433 is a prime.

It is a super-2 number, since 2×11210331313081² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11210331310081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605165656540 + 5605165656541.

It is an arithmetic number, because the mean of its divisors is an integer number (5605165656541).

Almost surely, 2^{11210331313081} is an apocalyptic number.

It is an amenable number.

11210331313081 is a deficient number, since it is larger than the sum of its proper divisors (1).

11210331313081 is an equidigital number, since it uses as much as digits as its factorization.

11210331313081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 28.

Adding to 11210331313081 its reverse (18031313301211), we get a palindrome (29241644614292).

The spelling of 11210331313081 in words is "eleven trillion, two hundred ten billion, three hundred thirty-one million, three hundred thirteen thousand, eighty-one".