Base | Representation |
---|---|
bin | 10000010100000011001… |
… | …101110000101100000111 |
3 | 10222011121020021222212121 |
4 | 100110003031300230013 |
5 | 121331342320400312 |
6 | 2214555430230411 |
7 | 143664266126644 |
oct | 20240315605407 |
9 | 3864536258777 |
10 | 1121040403207 |
11 | 3a248109a37a |
12 | 1613221b5407 |
13 | 81937b982ba |
14 | 3c389a16dcb |
15 | 1e262c2e707 |
hex | 10503370b07 |
1121040403207 has 2 divisors, whose sum is σ = 1121040403208. Its totient is φ = 1121040403206.
The previous prime is 1121040403199. The next prime is 1121040403267. The reversal of 1121040403207 is 7023040401211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121040403207 - 23 = 1121040403199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121040403267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560520201603 + 560520201604.
It is an arithmetic number, because the mean of its divisors is an integer number (560520201604).
Almost surely, 21121040403207 is an apocalyptic number.
1121040403207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121040403207 is an equidigital number, since it uses as much as digits as its factorization.
1121040403207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 1121040403207 its reverse (7023040401211), we get a palindrome (8144080804418).
The spelling of 1121040403207 in words is "one trillion, one hundred twenty-one billion, forty million, four hundred three thousand, two hundred seven".
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