112110000120221 has 4 divisors (see below), whose sum is σ = 112116861633600. Its totient is φ = 112103138606844.

The previous prime is 112110000120193. The next prime is 112110000120233. The reversal of 112110000120221 is 122021000011211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112110000120221 is a prime.

It is a super-3 number, since 3×112110000120221³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112110000120196 and 112110000120205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112110000120281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3430732181 + ... + 3430764858.

It is an arithmetic number, because the mean of its divisors is an integer number (28029215408400).

Almost surely, 2^{112110000120221} is an apocalyptic number.

It is an amenable number.

112110000120221 is a deficient number, since it is larger than the sum of its proper divisors (6861513379).

112110000120221 is an equidigital number, since it uses as much as digits as its factorization.

112110000120221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6861513378.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 112110000120221 its reverse (122021000011211), we get a palindrome (234131000131432).

The spelling of 112110000120221 in words is "one hundred twelve trillion, one hundred ten billion, one hundred twenty thousand, two hundred twenty-one".