Base | Representation |
---|---|
bin | 10100111000011101… |
… | …00100110010101011 |
3 | 1001221022110212012101 |
4 | 22130032210302223 |
5 | 140430004013003 |
6 | 5052242354231 |
7 | 544550636056 |
oct | 123416446253 |
9 | 31838425171 |
10 | 11211001003 |
11 | 4833354a94 |
12 | 220a65b977 |
13 | 1098864007 |
14 | 784d17a9d |
15 | 45936d11d |
hex | 29c3a4cab |
11211001003 has 2 divisors, whose sum is σ = 11211001004. Its totient is φ = 11211001002.
The previous prime is 11211000973. The next prime is 11211001007. The reversal of 11211001003 is 30010011211.
11211001003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (30010011211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11211001003 - 25 = 11211000971 is a prime.
It is not a weakly prime, because it can be changed into another prime (11211001007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605500501 + 5605500502.
It is an arithmetic number, because the mean of its divisors is an integer number (5605500502).
Almost surely, 211211001003 is an apocalyptic number.
11211001003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11211001003 is an equidigital number, since it uses as much as digits as its factorization.
11211001003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 10.
Adding to 11211001003 its reverse (30010011211), we get a palindrome (41221012214).
The spelling of 11211001003 in words is "eleven billion, two hundred eleven million, one thousand, three".
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