Base | Representation |
---|---|
bin | 10000010100000110110… |
… | …100110011000001101111 |
3 | 10222011202110021000012211 |
4 | 100110012310303001233 |
5 | 121332003321434142 |
6 | 2215005432311251 |
7 | 143665632665554 |
oct | 20240664630157 |
9 | 3864673230184 |
10 | 1121100968047 |
11 | 3a25022a6665 |
12 | 16133a542527 |
13 | 819475b2398 |
14 | 3c393aa0a2b |
15 | 1e2681e4917 |
hex | 10506d3306f |
1121100968047 has 2 divisors, whose sum is σ = 1121100968048. Its totient is φ = 1121100968046.
The previous prime is 1121100968017. The next prime is 1121100968123. The reversal of 1121100968047 is 7408690011211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121100968047 - 231 = 1118953484399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121100968017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560550484023 + 560550484024.
It is an arithmetic number, because the mean of its divisors is an integer number (560550484024).
Almost surely, 21121100968047 is an apocalyptic number.
1121100968047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121100968047 is an equidigital number, since it uses as much as digits as its factorization.
1121100968047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 40.
Adding to 1121100968047 its reverse (7408690011211), we get a palindrome (8529790979258).
The spelling of 1121100968047 in words is "one trillion, one hundred twenty-one billion, one hundred million, nine hundred sixty-eight thousand, forty-seven".
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