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11211013000212 = 223311491578831459
BaseRepresentation
bin1010001100100100010001…
…1100101000110000010100
31110200202120202211201222120
42203021010130220300110
52432140123312001322
635502133540255540
72234653232116554
oct243110434506024
943622522751876
1011211013000212
113632622628183
1213109296a15b0
1363426a26cbac
142aa88a14d164
151469568d9a5c
hexa3244728c14

11211013000212 has 192 divisors, whose sum is σ = 27406998528000. Its totient is φ = 3562818255360.

The previous prime is 11211013000211. The next prime is 11211013000241. The reversal of 11211013000212 is 21200031011211.

It is a junction number, because it is equal to n+sod(n) for n = 11211013000191 and 11211013000200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11211013000211) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7684038339 + ... + 7684039797.

It is an arithmetic number, because the mean of its divisors is an integer number (142744784000).

Almost surely, 211211013000212 is an apocalyptic number.

11211013000212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11211013000212 is an abundant number, since it is smaller than the sum of its proper divisors (16195985527788).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11211013000212 is a wasteful number, since it uses less digits than its factorization.

11211013000212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2686 (or 2684 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 11211013000212 its reverse (21200031011211), we get a palindrome (32411044011423).

The spelling of 11211013000212 in words is "eleven trillion, two hundred eleven billion, thirteen million, two hundred twelve", and thus it is an aban number.