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112111213023 = 3327115322019
BaseRepresentation
bin110100001101001011…
…0010101100111011111
3101201101020000201012000
41220122112111213133
53314100432304043
6123300404213343
711046135405315
oct1503226254737
9351336021160
10112111213023
1143600947767
121988999a253
13a758a12794
1455d774c0b5
152db26272d3
hex1a1a5959df

112111213023 has 16 divisors (see below), whose sum is σ = 166703577600. Its totient is φ = 74465007480.

The previous prime is 112111213007. The next prime is 112111213031. The reversal of 112111213023 is 320312111211.

It is not a de Polignac number, because 112111213023 - 24 = 112111213007 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112111212987 and 112111213005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112111214023) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7653693 + ... + 7668326.

It is an arithmetic number, because the mean of its divisors is an integer number (10418973600).

Almost surely, 2112111213023 is an apocalyptic number.

112111213023 is a deficient number, since it is larger than the sum of its proper divisors (54592364577).

112111213023 is a wasteful number, since it uses less digits than its factorization.

112111213023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15322299 (or 15322293 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 112111213023 its reverse (320312111211), we get a palindrome (432423324234).

The spelling of 112111213023 in words is "one hundred twelve billion, one hundred eleven million, two hundred thirteen thousand, twenty-three".

Divisors: 1 3 9 27 271 813 2439 7317 15322019 45966057 137898171 413694513 4152267149 12456801447 37370404341 112111213023