112111433343331 has 4 divisors (see below), whose sum is σ = 112224562944064. Its totient is φ = 111998303742600.

The previous prime is 112111433343263. The next prime is 112111433343361. The reversal of 112111433343331 is 133343334111211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112111433343331 - 2⁹ = 112111433342819 is a prime.

It is a super-3 number, since 3×112111433343331³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112111433343361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56564798880 + ... + 56564800861.

It is an arithmetic number, because the mean of its divisors is an integer number (28056140736016).

Almost surely, 2^{112111433343331} is an apocalyptic number.

112111433343331 is a deficient number, since it is larger than the sum of its proper divisors (113129600733).

112111433343331 is an equidigital number, since it uses as much as digits as its factorization.

112111433343331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113129600732.

The product of its digits is 23328, while the sum is 34.

Adding to 112111433343331 its reverse (133343334111211), we get a palindrome (245454767454542).

The spelling of 112111433343331 in words is "one hundred twelve trillion, one hundred eleven billion, four hundred thirty-three million, three hundred forty-three thousand, three hundred thirty-one".