Base | Representation |
---|---|
bin | 10100111000011110… |
… | …10101110111110001 |
3 | 1001221022212001221221 |
4 | 22130033111313301 |
5 | 140430031431113 |
6 | 5052250545041 |
7 | 544552434133 |
oct | 123417256761 |
9 | 31838761857 |
10 | 11211202033 |
11 | 4833482029 |
12 | 220a738181 |
13 | 1098904675 |
14 | 784d6b053 |
15 | 4593ac98d |
hex | 29c3d5df1 |
11211202033 has 4 divisors (see below), whose sum is σ = 11212145008. Its totient is φ = 11210259060.
The previous prime is 11211202027. The next prime is 11211202061. The reversal of 11211202033 is 33020211211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11211202033 - 213 = 11211193841 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11211201998 and 11211202016.
It is not an unprimeable number, because it can be changed into a prime (11211202003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 453423 + ... + 477508.
It is an arithmetic number, because the mean of its divisors is an integer number (2803036252).
Almost surely, 211211202033 is an apocalyptic number.
It is an amenable number.
11211202033 is a deficient number, since it is larger than the sum of its proper divisors (942975).
11211202033 is an equidigital number, since it uses as much as digits as its factorization.
11211202033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 942974.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 11211202033 its reverse (33020211211), we get a palindrome (44231413244).
The spelling of 11211202033 in words is "eleven billion, two hundred eleven million, two hundred two thousand, thirty-three".
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