Base | Representation |
---|---|
bin | 110100001101001100… |
… | …1101110001001101111 |
3 | 101201101021200202211012 |
4 | 1220122121232021233 |
5 | 3314101144144301 |
6 | 123300435215435 |
7 | 11046146061155 |
oct | 1503231561157 |
9 | 351337622735 |
10 | 112112099951 |
11 | 436013a3065 |
12 | 1988a14757b |
13 | a758c633a7 |
14 | 55d78dd3d5 |
15 | 2db274eebb |
hex | 1a1a66e26f |
112112099951 has 2 divisors, whose sum is σ = 112112099952. Its totient is φ = 112112099950.
The previous prime is 112112099933. The next prime is 112112100049. The reversal of 112112099951 is 159990211211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112112099951 - 210 = 112112098927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112112099899 and 112112099908.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112112099251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056049975 + 56056049976.
It is an arithmetic number, because the mean of its divisors is an integer number (56056049976).
Almost surely, 2112112099951 is an apocalyptic number.
112112099951 is a deficient number, since it is larger than the sum of its proper divisors (1).
112112099951 is an equidigital number, since it uses as much as digits as its factorization.
112112099951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 41.
The spelling of 112112099951 in words is "one hundred twelve billion, one hundred twelve million, ninety-nine thousand, nine hundred fifty-one".
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