Base | Representation |
---|---|
bin | 1010001100100101000001… |
… | …0100111100011101110111 |
3 | 1110200210002122212202011001 |
4 | 2203021100110330131313 |
5 | 2432141030322413031 |
6 | 35502205420224131 |
7 | 2234661202202032 |
oct | 243112024743567 |
9 | 43623078782131 |
10 | 11211212310391 |
11 | 3632715089935 |
12 | 131098439b047 |
13 | 63429c645202 |
14 | 2aa8a87d2019 |
15 | 146969159861 |
hex | a325053c777 |
11211212310391 has 2 divisors, whose sum is σ = 11211212310392. Its totient is φ = 11211212310390.
The previous prime is 11211212310373. The next prime is 11211212310401. The reversal of 11211212310391 is 19301321211211.
11211212310391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11211212310391 - 211 = 11211212308343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11211212310091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605606155195 + 5605606155196.
It is an arithmetic number, because the mean of its divisors is an integer number (5605606155196).
Almost surely, 211211212310391 is an apocalyptic number.
11211212310391 is a deficient number, since it is larger than the sum of its proper divisors (1).
11211212310391 is an equidigital number, since it uses as much as digits as its factorization.
11211212310391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 28.
The spelling of 11211212310391 in words is "eleven trillion, two hundred eleven billion, two hundred twelve million, three hundred ten thousand, three hundred ninety-one".
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