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112112131311281 is a prime number
BaseRepresentation
bin11001011111011100100011…
…110000110000011010110001
3112200221211000012020102220002
4121133130203300300122301
5104143321121103430111
61034235334015555345
732420556061451603
oct3137344360603261
9480854005212802
10112112131311281
11327a4540405872
12106a80b9b2bb55
134a7318976435a
141d98382a91173
15ce646198763b
hex65f723c306b1

112112131311281 has 2 divisors, whose sum is σ = 112112131311282. Its totient is φ = 112112131311280.

The previous prime is 112112131311277. The next prime is 112112131311347. The reversal of 112112131311281 is 182113131211211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106757146552225 + 5354984759056 = 10332335^2 + 2314084^2 .

It is a cyclic number.

It is not a de Polignac number, because 112112131311281 - 22 = 112112131311277 is a prime.

It is a super-2 number, since 2×1121121313112812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112112136311281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056065655640 + 56056065655641.

It is an arithmetic number, because the mean of its divisors is an integer number (56056065655641).

Almost surely, 2112112131311281 is an apocalyptic number.

It is an amenable number.

112112131311281 is a deficient number, since it is larger than the sum of its proper divisors (1).

112112131311281 is an equidigital number, since it uses as much as digits as its factorization.

112112131311281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 576, while the sum is 29.

Adding to 112112131311281 its reverse (182113131211211), we get a palindrome (294225262522492).

The spelling of 112112131311281 in words is "one hundred twelve trillion, one hundred twelve billion, one hundred thirty-one million, three hundred eleven thousand, two hundred eighty-one".