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1121121430031 is a prime number
BaseRepresentation
bin10000010100001000000…
…010110110101000001111
310222011210212202120210002
4100110020002312220033
5121332024041230111
62215011443034515
7143666301630521
oct20241002665017
93864725676702
101121121430031
113a2512901a99
1216134536ba3b
138194b8c7b75
143c3966a9a11
151e269dd763b
hex105080b6a0f

1121121430031 has 2 divisors, whose sum is σ = 1121121430032. Its totient is φ = 1121121430030.

The previous prime is 1121121430027. The next prime is 1121121430129. The reversal of 1121121430031 is 1300341211211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1121121430031 - 22 = 1121121430027 is a prime.

It is a super-2 number, since 2×11211214300312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1121121429985 and 1121121430012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121121430631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560560715015 + 560560715016.

It is an arithmetic number, because the mean of its divisors is an integer number (560560715016).

Almost surely, 21121121430031 is an apocalyptic number.

1121121430031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121121430031 is an equidigital number, since it uses as much as digits as its factorization.

1121121430031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1121121430031 its reverse (1300341211211), we get a palindrome (2421462641242).

The spelling of 1121121430031 in words is "one trillion, one hundred twenty-one billion, one hundred twenty-one million, four hundred thirty thousand, thirty-one".