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112112143011157 is a prime number
BaseRepresentation
bin11001011111011100100100…
…011101011000110101010101
3112200221211001000020212002211
4121133130210131120311111
5104143321132102324112
61034235335114433421
732420556263061202
oct3137344435306525
9480854030225084
10112112143011157
11327a4546a77093
12106a8101a32871
134a7318bccc863
141d98384458ca9
15ce64629e90a7
hex65f724758d55

112112143011157 has 2 divisors, whose sum is σ = 112112143011158. Its totient is φ = 112112143011156.

The previous prime is 112112143011139. The next prime is 112112143011199. The reversal of 112112143011157 is 751110341211211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85295550042481 + 26816592968676 = 9235559^2 + 5178474^2 .

It is a cyclic number.

It is not a de Polignac number, because 112112143011157 - 211 = 112112143009109 is a prime.

It is a super-2 number, since 2×1121121430111572 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112112143017157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056071505578 + 56056071505579.

It is an arithmetic number, because the mean of its divisors is an integer number (56056071505579).

Almost surely, 2112112143011157 is an apocalyptic number.

It is an amenable number.

112112143011157 is a deficient number, since it is larger than the sum of its proper divisors (1).

112112143011157 is an equidigital number, since it uses as much as digits as its factorization.

112112143011157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1680, while the sum is 31.

Adding to 112112143011157 its reverse (751110341211211), we get a palindrome (863222484222368).

The spelling of 112112143011157 in words is "one hundred twelve trillion, one hundred twelve billion, one hundred forty-three million, eleven thousand, one hundred fifty-seven".