1121122120123 has 2 divisors, whose sum is σ = 1121122120124. Its totient is φ = 1121122120122.

The previous prime is 1121122120121. The next prime is 1121122120133. The reversal of 1121122120123 is 3210212211211.

It is a weak prime.

It is an emirp because it is prime and its reverse (3210212211211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1121122120123 - 2¹ = 1121122120121 is a prime.

It is a super-3 number, since 3×1121122120123³ (a number of 37 digits) contains 333 as substring.

Together with 1121122120121, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1121122120123.

It is not a weakly prime, because it can be changed into another prime (1121122120121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560561060061 + 560561060062.

It is an arithmetic number, because the mean of its divisors is an integer number (560561060062).

Almost surely, 2^{1121122120123} is an apocalyptic number.

1121122120123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121122120123 is an equidigital number, since it uses as much as digits as its factorization.

1121122120123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1121122120123 its reverse (3210212211211), we get a palindrome (4331334331334).

The spelling of 1121122120123 in words is "one trillion, one hundred twenty-one billion, one hundred twenty-two million, one hundred twenty thousand, one hundred twenty-three".