Base | Representation |
---|---|
bin | 10000010100001000000… |
… | …101110111100000001111 |
3 | 10222011210221020201110221 |
4 | 100110020011313200033 |
5 | 121332024242020142 |
6 | 2215011512012211 |
7 | 143666311431004 |
oct | 20241005674017 |
9 | 3864727221427 |
10 | 1121122220047 |
11 | 3a25132a15a5 |
12 | 161345691067 |
13 | 8194bb1362b |
14 | 3c3968338ab |
15 | 1e269ee1767 |
hex | 1050817780f |
1121122220047 has 2 divisors, whose sum is σ = 1121122220048. Its totient is φ = 1121122220046.
The previous prime is 1121122220003. The next prime is 1121122220083. The reversal of 1121122220047 is 7400222211211.
It is a strong prime.
It is an emirp because it is prime and its reverse (7400222211211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1121122220047 - 215 = 1121122187279 is a prime.
It is a super-2 number, since 2×11211222200472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121122226047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560561110023 + 560561110024.
It is an arithmetic number, because the mean of its divisors is an integer number (560561110024).
Almost surely, 21121122220047 is an apocalyptic number.
1121122220047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121122220047 is an equidigital number, since it uses as much as digits as its factorization.
1121122220047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 1121122220047 its reverse (7400222211211), we get a palindrome (8521344431258).
The spelling of 1121122220047 in words is "one trillion, one hundred twenty-one billion, one hundred twenty-two million, two hundred twenty thousand, forty-seven".
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