Base | Representation |
---|---|
bin | 110100001101001110… |
… | …1100010011000001111 |
3 | 101201101100120121001021 |
4 | 1220122131202120033 |
5 | 3314101423202203 |
6 | 123300512455011 |
7 | 11046160425511 |
oct | 1503235423017 |
9 | 351340517037 |
10 | 112113100303 |
11 | 43601a166a6 |
12 | 1988a54a467 |
13 | a759223809 |
14 | 55d7abdbb1 |
15 | 2db289b5bd |
hex | 1a1a76260f |
112113100303 has 4 divisors (see below), whose sum is σ = 112175770120. Its totient is φ = 112050430488.
The previous prime is 112113100289. The next prime is 112113100343. The reversal of 112113100303 is 303001311211.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303001311211 = 137 ⋅2211688403.
It is a cyclic number.
It is not a de Polignac number, because 112113100303 - 25 = 112113100271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112113100343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31332225 + ... + 31335802.
It is an arithmetic number, because the mean of its divisors is an integer number (28043942530).
Almost surely, 2112113100303 is an apocalyptic number.
112113100303 is a deficient number, since it is larger than the sum of its proper divisors (62669817).
112113100303 is an equidigital number, since it uses as much as digits as its factorization.
112113100303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62669816.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 112113100303 its reverse (303001311211), we get a palindrome (415114411514).
The spelling of 112113100303 in words is "one hundred twelve billion, one hundred thirteen million, one hundred thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •