Base | Representation |
---|---|
bin | 1010001100100101011001… |
… | …0101100000011101010111 |
3 | 1110200210100200120110110102 |
4 | 2203021112111200131113 |
5 | 2432141232124333421 |
6 | 35502223421044315 |
7 | 2234663535111605 |
oct | 243112625403527 |
9 | 43623320513412 |
10 | 11211313121111 |
11 | 3632766a84484 |
12 | 13109b20b669b |
13 | 6342b74b0a1c |
14 | 2aa8b7d54875 |
15 | 146972e1e60b |
hex | a3256560757 |
11211313121111 has 2 divisors, whose sum is σ = 11211313121112. Its totient is φ = 11211313121110.
The previous prime is 11211313121093. The next prime is 11211313121147. The reversal of 11211313121111 is 11112131311211.
It is a m-pointer prime, because the next prime (11211313121147) can be obtained adding 11211313121111 to its product of digits (36).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11211313121111 - 226 = 11211246012247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11211313124111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605656560555 + 5605656560556.
It is an arithmetic number, because the mean of its divisors is an integer number (5605656560556).
Almost surely, 211211313121111 is an apocalyptic number.
11211313121111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11211313121111 is an equidigital number, since it uses as much as digits as its factorization.
11211313121111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 36, while the sum is 20.
Adding to 11211313121111 its reverse (11112131311211), we get a palindrome (22323444432322).
The spelling of 11211313121111 in words is "eleven trillion, two hundred eleven billion, three hundred thirteen million, one hundred twenty-one thousand, one hundred eleven".
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