Base | Representation |
---|---|
bin | 10000010100001000101… |
… | …111001001011000011111 |
3 | 10222011211200121111021202 |
4 | 100110020233021120133 |
5 | 121332040024304213 |
6 | 2215012535550115 |
7 | 143666502420341 |
oct | 20241057113037 |
9 | 3864750544252 |
10 | 1121133041183 |
11 | 3a2519412691 |
12 | 16134922b33b |
13 | 81951131b7c |
14 | 3c39804d291 |
15 | 1e26ae2cb58 |
hex | 10508bc961f |
1121133041183 has 2 divisors, whose sum is σ = 1121133041184. Its totient is φ = 1121133041182.
The previous prime is 1121133041137. The next prime is 1121133041263. The reversal of 1121133041183 is 3811403311211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121133041183 - 214 = 1121133024799 is a prime.
It is a super-3 number, since 3×11211330411833 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121133041983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560566520591 + 560566520592.
It is an arithmetic number, because the mean of its divisors is an integer number (560566520592).
Almost surely, 21121133041183 is an apocalyptic number.
1121133041183 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121133041183 is an equidigital number, since it uses as much as digits as its factorization.
1121133041183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 29.
Adding to 1121133041183 its reverse (3811403311211), we get a palindrome (4932536352394).
The spelling of 1121133041183 in words is "one trillion, one hundred twenty-one billion, one hundred thirty-three million, forty-one thousand, one hundred eighty-three".
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