Base | Representation |
---|---|
bin | 10100111000011111… |
… | …10101011100000010 |
3 | 1001221100002122022201 |
4 | 22130033311130002 |
5 | 140430100100310 |
6 | 5052253423414 |
7 | 544553513113 |
oct | 123417653402 |
9 | 31840078281 |
10 | 11211331330 |
11 | 4833560191 |
12 | 220a79ab6a |
13 | 109894b484 |
14 | 784da220a |
15 | 4593d5e3a |
hex | 29c3f5702 |
11211331330 has 32 divisors (see below), whose sum is σ = 21280060800. Its totient is φ = 4240996992.
The previous prime is 11211331303. The next prime is 11211331361. The reversal of 11211331330 is 3313311211.
11211331330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is a junction number, because it is equal to n+sod(n) for n = 11211331298 and 11211331307.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56259 + ... + 159961.
It is an arithmetic number, because the mean of its divisors is an integer number (665001900).
Almost surely, 211211331330 is an apocalyptic number.
11211331330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11211331330 is a deficient number, since it is larger than the sum of its proper divisors (10068729470).
11211331330 is a wasteful number, since it uses less digits than its factorization.
11211331330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104298.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 11211331330 its reverse (3313311211), we get a palindrome (14524642541).
The spelling of 11211331330 in words is "eleven billion, two hundred eleven million, three hundred thirty-one thousand, three hundred thirty".
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