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11211450402433 is a prime number
BaseRepresentation
bin1010001100100101111010…
…0001001100011010000001
31110200210201020220002000211
42203021132201030122001
52432142022300334213
635502245203314121
72235000123016651
oct243113641143201
943623636802024
1011211450402433
113632827519a16
121310a3007b941
13634309a78788
142aa8cc28c361
1514697eeda53d
hexa325e84c681

11211450402433 has 2 divisors, whose sum is σ = 11211450402434. Its totient is φ = 11211450402432.

The previous prime is 11211450402413. The next prime is 11211450402577. The reversal of 11211450402433 is 33420405411211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8254261158529 + 2957189243904 = 2873023^2 + 1719648^2 .

It is a cyclic number.

It is not a de Polignac number, because 11211450402433 - 217 = 11211450271361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11211450402395 and 11211450402404.

It is not a weakly prime, because it can be changed into another prime (11211450402413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605725201216 + 5605725201217.

It is an arithmetic number, because the mean of its divisors is an integer number (5605725201217).

Almost surely, 211211450402433 is an apocalyptic number.

It is an amenable number.

11211450402433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11211450402433 is an equidigital number, since it uses as much as digits as its factorization.

11211450402433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 11211450402433 its reverse (33420405411211), we get a palindrome (44631855813644).

The spelling of 11211450402433 in words is "eleven trillion, two hundred eleven billion, four hundred fifty million, four hundred two thousand, four hundred thirty-three".