Base | Representation |
---|---|
bin | 11001011111100011111001… |
… | …011000000010001110100111 |
3 | 112200222120100021121111120002 |
4 | 121133203321120002032213 |
5 | 104143433240042402101 |
6 | 1034243115510131515 |
7 | 32421255241315643 |
oct | 3137437130021647 |
9 | 480876307544502 |
10 | 112120010122151 |
11 | 327a791382a009 |
12 | 106a9738650b9b |
13 | 4a73b43b55215 |
14 | 1d988cd20dc23 |
15 | ce67734e4d6b |
hex | 65f8f96023a7 |
112120010122151 has 2 divisors, whose sum is σ = 112120010122152. Its totient is φ = 112120010122150.
The previous prime is 112120010122093. The next prime is 112120010122157. The reversal of 112120010122151 is 151221010021211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112120010122151 - 242 = 107721963611047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112120010122157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060005061075 + 56060005061076.
It is an arithmetic number, because the mean of its divisors is an integer number (56060005061076).
Almost surely, 2112120010122151 is an apocalyptic number.
112120010122151 is a deficient number, since it is larger than the sum of its proper divisors (1).
112120010122151 is an equidigital number, since it uses as much as digits as its factorization.
112120010122151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 112120010122151 its reverse (151221010021211), we get a palindrome (263341020143362).
The spelling of 112120010122151 in words is "one hundred twelve trillion, one hundred twenty billion, ten million, one hundred twenty-two thousand, one hundred fifty-one".
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