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11212002018083 is a prime number
BaseRepresentation
bin1010001100100111111101…
…1001011100001100100011
31110200212010200212001110002
42203021333121130030203
52432144140004034313
635502420030330215
72235016601460566
oct243117731341443
943625120761402
1011212002018083
113632a8a92aa19
121310b6495996b
13634397133479
142aa94163c4dd
151469b364c058
hexa327f65c323

11212002018083 has 2 divisors, whose sum is σ = 11212002018084. Its totient is φ = 11212002018082.

The previous prime is 11212002018059. The next prime is 11212002018121. The reversal of 11212002018083 is 38081020021211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11212002018083 - 218 = 11212001755939 is a prime.

It is a super-3 number, since 3×112120020180833 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11212002018013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606001009041 + 5606001009042.

It is an arithmetic number, because the mean of its divisors is an integer number (5606001009042).

Almost surely, 211212002018083 is an apocalyptic number.

11212002018083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212002018083 is an equidigital number, since it uses as much as digits as its factorization.

11212002018083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 29.

Adding to 11212002018083 its reverse (38081020021211), we get a palindrome (49293022039294).

The spelling of 11212002018083 in words is "eleven trillion, two hundred twelve billion, two million, eighteen thousand, eighty-three".