Base | Representation |
---|---|
bin | 11001011111100011111111… |
… | …010101011011001000010011 |
3 | 112200222120121020201221202211 |
4 | 121133203333111123020103 |
5 | 104143433441141213021 |
6 | 1034243133441052551 |
7 | 32421260564162335 |
oct | 3137437725331023 |
9 | 480876536657684 |
10 | 112120110101011 |
11 | 327a7965206671 |
12 | 106a9766027157 |
13 | 4a73b5b78c1cc |
14 | 1d988dc5d7455 |
15 | ce677c1933e1 |
hex | 65f8ff55b213 |
112120110101011 has 4 divisors (see below), whose sum is σ = 118021168527400. Its totient is φ = 106219051674624.
The previous prime is 112120110101003. The next prime is 112120110101047. The reversal of 112120110101011 is 110101011021211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 112120110101011 - 23 = 112120110101003 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 112120110100982 and 112120110101000.
It is not an unprimeable number, because it can be changed into a prime (112120110104011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2950529213166 + ... + 2950529213203.
It is an arithmetic number, because the mean of its divisors is an integer number (29505292131850).
Almost surely, 2112120110101011 is an apocalyptic number.
112120110101011 is a deficient number, since it is larger than the sum of its proper divisors (5901058426389).
112120110101011 is an equidigital number, since it uses as much as digits as its factorization.
112120110101011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5901058426388.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 112120110101011 its reverse (110101011021211), we get a palindrome (222221121122222).
The spelling of 112120110101011 in words is "one hundred twelve trillion, one hundred twenty billion, one hundred ten million, one hundred one thousand, eleven".
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