Base | Representation |
---|---|
bin | 1010001100100111111111… |
… | …1100001000001010101011 |
3 | 1110200212011022222000200212 |
4 | 2203021333330020022223 |
5 | 2432144144321023313 |
6 | 35502420553251335 |
7 | 2235020041662026 |
oct | 243117774101253 |
9 | 43625138860625 |
10 | 11212011111083 |
11 | 3632a94a806a2 |
12 | 1310b67a03b4b |
13 | 634398c98243 |
14 | 2aa9429281bd |
15 | 1469b43463a8 |
hex | a327ff082ab |
11212011111083 has 2 divisors, whose sum is σ = 11212011111084. Its totient is φ = 11212011111082.
The previous prime is 11212011111047. The next prime is 11212011111109. The reversal of 11212011111083 is 38011111021211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11212011111083 - 220 = 11212010062507 is a prime.
It is not a weakly prime, because it can be changed into another prime (11212011111383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606005555541 + 5606005555542.
It is an arithmetic number, because the mean of its divisors is an integer number (5606005555542).
Almost surely, 211212011111083 is an apocalyptic number.
11212011111083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212011111083 is an equidigital number, since it uses as much as digits as its factorization.
11212011111083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 23.
Adding to 11212011111083 its reverse (38011111021211), we get a palindrome (49223122132294).
The spelling of 11212011111083 in words is "eleven trillion, two hundred twelve billion, eleven million, one hundred eleven thousand, eighty-three".
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