Base | Representation |
---|---|
bin | 10100111000100100… |
… | …11011111001011101 |
3 | 1001221101101021121021 |
4 | 22130102123321131 |
5 | 140430233410044 |
6 | 5052320204141 |
7 | 544562352661 |
oct | 123422337135 |
9 | 31841337537 |
10 | 11212013149 |
11 | 4833986477 |
12 | 220aa69651 |
13 | 1098b2990c |
14 | 7850dc8a1 |
15 | 4594bce84 |
hex | 29c49be5d |
11212013149 has 2 divisors, whose sum is σ = 11212013150. Its totient is φ = 11212013148.
The previous prime is 11212013081. The next prime is 11212013173. The reversal of 11212013149 is 94131021211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9291996025 + 1920017124 = 96395^2 + 43818^2 .
It is an emirp because it is prime and its reverse (94131021211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11212013149 - 223 = 11203624541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212013249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606006574 + 5606006575.
It is an arithmetic number, because the mean of its divisors is an integer number (5606006575).
Almost surely, 211212013149 is an apocalyptic number.
It is an amenable number.
11212013149 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212013149 is an equidigital number, since it uses as much as digits as its factorization.
11212013149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 11212013149 in words is "eleven billion, two hundred twelve million, thirteen thousand, one hundred forty-nine".
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