Base | Representation |
---|---|
bin | 1010001100101000000010… |
… | …0101101101000100001111 |
3 | 1110200212012002110202101011 |
4 | 2203022000211231010033 |
5 | 2432144210113311002 |
6 | 35502422023030051 |
7 | 2235020233424461 |
oct | 243120045550417 |
9 | 43625162422334 |
10 | 11212022010127 |
11 | 3632aa0145274 |
12 | 1310b6b59b327 |
13 | 63439b313093 |
14 | 2aa944164131 |
15 | 1469b529a8d7 |
hex | a328096d10f |
11212022010127 has 2 divisors, whose sum is σ = 11212022010128. Its totient is φ = 11212022010126.
The previous prime is 11212022010061. The next prime is 11212022010151. The reversal of 11212022010127 is 72101022021211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11212022010127 - 231 = 11209874526479 is a prime.
It is a super-2 number, since 2×112120220101272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11212022010098 and 11212022010107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212022010727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606011005063 + 5606011005064.
It is an arithmetic number, because the mean of its divisors is an integer number (5606011005064).
Almost surely, 211212022010127 is an apocalyptic number.
11212022010127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212022010127 is an equidigital number, since it uses as much as digits as its factorization.
11212022010127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 11212022010127 its reverse (72101022021211), we get a palindrome (83313044031338).
The spelling of 11212022010127 in words is "eleven trillion, two hundred twelve billion, twenty-two million, ten thousand, one hundred twenty-seven".
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