Base | Representation |
---|---|
bin | 10100111000100101… |
… | …00011000110001011 |
3 | 1001221101102210001100 |
4 | 22130102203012023 |
5 | 140430240331020 |
6 | 5052320552443 |
7 | 544562534643 |
oct | 123422430613 |
9 | 31841383040 |
10 | 11212042635 |
11 | 48339a6642 |
12 | 220aa82723 |
13 | 1098b3a171 |
14 | 785109523 |
15 | 4594c6a90 |
hex | 29c4a318b |
11212042635 has 24 divisors (see below), whose sum is σ = 19546557264. Its totient is φ = 5945186880.
The previous prime is 11212042631. The next prime is 11212042651. The reversal of 11212042635 is 53624021211.
11212042635 is a `hidden beast` number, since 1 + 1 + 2 + 1 + 20 + 4 + 2 + 635 = 666.
It is not a de Polignac number, because 11212042635 - 22 = 11212042631 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11212042599 and 11212042608.
It is not an unprimeable number, because it can be changed into a prime (11212042631) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 712321 + ... + 727890.
It is an arithmetic number, because the mean of its divisors is an integer number (814439886).
Almost surely, 211212042635 is an apocalyptic number.
11212042635 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11212042635 is a deficient number, since it is larger than the sum of its proper divisors (8334514629).
11212042635 is a wasteful number, since it uses less digits than its factorization.
11212042635 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1440395 (or 1440392 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 11212042635 its reverse (53624021211), we get a palindrome (64836063846).
The spelling of 11212042635 in words is "eleven billion, two hundred twelve million, forty-two thousand, six hundred thirty-five".
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