Base | Representation |
---|---|
bin | 11001011111100100110100… |
… | …011000100101001111010100 |
3 | 112200222122220021110200002020 |
4 | 121133210310120211033110 |
5 | 104143442302012340200 |
6 | 1034243402033213140 |
7 | 32421321622214562 |
oct | 3137446430451724 |
9 | 480878807420066 |
10 | 112121000121300 |
11 | 327a8281642025 |
12 | 106a99741011b0 |
13 | 4a73c70ca0331 |
14 | 1d989848b6a32 |
15 | ce67d039cea0 |
hex | 65f9346253d4 |
112121000121300 has 216 divisors, whose sum is σ = 334352401639200. Its totient is φ = 29007590572800.
The previous prime is 112121000121293. The next prime is 112121000121373. The reversal of 112121000121300 is 3121000121211.
It is a super-2 number, since 2×1121210001213002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 112121000121300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 81972015 + ... + 83328585.
Almost surely, 2112121000121300 is an apocalyptic number.
112121000121300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112121000121300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167176200819600).
112121000121300 is an abundant number, since it is smaller than the sum of its proper divisors (222231401517900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112121000121300 is a wasteful number, since it uses less digits than its factorization.
112121000121300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1356823 (or 1356773 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 112121000121300 its reverse (3121000121211), we get a palindrome (115242000242511).
The spelling of 112121000121300 in words is "one hundred twelve trillion, one hundred twenty-one billion, one hundred twenty-one thousand, three hundred".
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