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112121000211169 is a prime number
BaseRepresentation
bin11001011111100100110100…
…011000111011001011100001
3112200222122220021122020100201
4121133210310120323023201
5104143442302023224134
61034243402035145201
732421321623040565
oct3137446430731341
9480878807566321
10112121000211169
11327a82816a35a4
12106a9974145201
134a73c71002201
141d989848db6a5
15ce67d03b9914
hex65f93463b2e1

112121000211169 has 2 divisors, whose sum is σ = 112121000211170. Its totient is φ = 112121000211168.

The previous prime is 112121000211167. The next prime is 112121000211211. The reversal of 112121000211169 is 961112000121211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108041056718400 + 4079943492769 = 10394280^2 + 2019887^2 .

It is a cyclic number.

It is not a de Polignac number, because 112121000211169 - 21 = 112121000211167 is a prime.

It is a super-3 number, since 3×1121210002111693 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 112121000211167, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (112121000211161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060500105584 + 56060500105585.

It is an arithmetic number, because the mean of its divisors is an integer number (56060500105585).

Almost surely, 2112121000211169 is an apocalyptic number.

It is an amenable number.

112121000211169 is a deficient number, since it is larger than the sum of its proper divisors (1).

112121000211169 is an equidigital number, since it uses as much as digits as its factorization.

112121000211169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 28.

The spelling of 112121000211169 in words is "one hundred twelve trillion, one hundred twenty-one billion, two hundred eleven thousand, one hundred sixty-nine".