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11212101312 = 26358396361
BaseRepresentation
bin10100111000100101…
…10001011011000000
31001221101112202112120
422130102301123000
5140430244220222
65052322124240
7544563201006
oct123422613300
931841482476
1011212101312
114833a36735
12220aab0680
131098b5aa99
14785122a76
154594d915c
hex29c4b16c0

11212101312 has 28 divisors (see below), whose sum is σ = 29665351896. Its totient is φ = 3737367040.

The previous prime is 11212101301. The next prime is 11212101337. The reversal of 11212101312 is 21310121211.

It is a super-2 number, since 2×112121013122 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11212101291 and 11212101300.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29197989 + ... + 29198372.

Almost surely, 211212101312 is an apocalyptic number.

11212101312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11212101312 is an abundant number, since it is smaller than the sum of its proper divisors (18453250584).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11212101312 is an equidigital number, since it uses as much as digits as its factorization.

11212101312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58396376 (or 58396366 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 11212101312 its reverse (21310121211), we get a palindrome (32522222523).

The spelling of 11212101312 in words is "eleven billion, two hundred twelve million, one hundred one thousand, three hundred twelve".

Divisors: 1 2 3 4 6 8 12 16 24 32 48 64 96 192 58396361 116792722 175189083 233585444 350378166 467170888 700756332 934341776 1401512664 1868683552 2803025328 3737367104 5606050656 11212101312