Base | Representation |
---|---|
bin | 10100111000100101… |
… | …10001011011000000 |
3 | 1001221101112202112120 |
4 | 22130102301123000 |
5 | 140430244220222 |
6 | 5052322124240 |
7 | 544563201006 |
oct | 123422613300 |
9 | 31841482476 |
10 | 11212101312 |
11 | 4833a36735 |
12 | 220aab0680 |
13 | 1098b5aa99 |
14 | 785122a76 |
15 | 4594d915c |
hex | 29c4b16c0 |
11212101312 has 28 divisors (see below), whose sum is σ = 29665351896. Its totient is φ = 3737367040.
The previous prime is 11212101301. The next prime is 11212101337. The reversal of 11212101312 is 21310121211.
It is a super-2 number, since 2×112121013122 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11212101291 and 11212101300.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29197989 + ... + 29198372.
Almost surely, 211212101312 is an apocalyptic number.
11212101312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11212101312 is an abundant number, since it is smaller than the sum of its proper divisors (18453250584).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11212101312 is an equidigital number, since it uses as much as digits as its factorization.
11212101312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58396376 (or 58396366 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 11212101312 its reverse (21310121211), we get a palindrome (32522222523).
The spelling of 11212101312 in words is "eleven billion, two hundred twelve million, one hundred one thousand, three hundred twelve".
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