Base | Representation |
---|---|
bin | 10000010100001101011… |
… | …000100101010110011111 |
3 | 10222012001010022211211201 |
4 | 100110031120211112133 |
5 | 121332220004400021 |
6 | 2215024403100331 |
7 | 144001440234112 |
oct | 20241530452637 |
9 | 3865033284751 |
10 | 1121211012511 |
11 | 3a25594286a7 |
12 | 16136b3716a7 |
13 | 81964331a55 |
14 | 3c3a4548579 |
15 | 1e272bd0591 |
hex | 1050d62559f |
1121211012511 has 2 divisors, whose sum is σ = 1121211012512. Its totient is φ = 1121211012510.
The previous prime is 1121211012457. The next prime is 1121211012553. The reversal of 1121211012511 is 1152101121211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121211012511 is a prime.
It is a super-2 number, since 2×11212110125112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121211013511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560605506255 + 560605506256.
It is an arithmetic number, because the mean of its divisors is an integer number (560605506256).
Almost surely, 21121211012511 is an apocalyptic number.
1121211012511 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121211012511 is an equidigital number, since it uses as much as digits as its factorization.
1121211012511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 19.
Adding to 1121211012511 its reverse (1152101121211), we get a palindrome (2273312133722).
The spelling of 1121211012511 in words is "one trillion, one hundred twenty-one billion, two hundred eleven million, twelve thousand, five hundred eleven".
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