Base | Representation |
---|---|
bin | 11001011111100100111010… |
… | …111111111011101010110011 |
3 | 112200222200012000021222100112 |
4 | 121133210322333323222303 |
5 | 104143443013420200313 |
6 | 1034243421040011535 |
7 | 32421324440424101 |
oct | 3137447277735263 |
9 | 480880160258315 |
10 | 112121111100083 |
11 | 327a8329252028 |
12 | 106a99a5300bab |
13 | 4a73c8ac89057 |
14 | 1d98995524c71 |
15 | ce67d9ec08a8 |
hex | 65f93affbab3 |
112121111100083 has 2 divisors, whose sum is σ = 112121111100084. Its totient is φ = 112121111100082.
The previous prime is 112121111100079. The next prime is 112121111100091. The reversal of 112121111100083 is 380001111121211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112121111100083 - 22 = 112121111100079 is a prime.
It is a super-2 number, since 2×1121211111000832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112121111100023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060555550041 + 56060555550042.
It is an arithmetic number, because the mean of its divisors is an integer number (56060555550042).
Almost surely, 2112121111100083 is an apocalyptic number.
112121111100083 is a deficient number, since it is larger than the sum of its proper divisors (1).
112121111100083 is an equidigital number, since it uses as much as digits as its factorization.
112121111100083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 23.
Adding to 112121111100083 its reverse (380001111121211), we get a palindrome (492122222221294).
The spelling of 112121111100083 in words is "one hundred twelve trillion, one hundred twenty-one billion, one hundred eleven million, one hundred thousand, eighty-three".
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