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112121111100083 is a prime number
BaseRepresentation
bin11001011111100100111010…
…111111111011101010110011
3112200222200012000021222100112
4121133210322333323222303
5104143443013420200313
61034243421040011535
732421324440424101
oct3137447277735263
9480880160258315
10112121111100083
11327a8329252028
12106a99a5300bab
134a73c8ac89057
141d98995524c71
15ce67d9ec08a8
hex65f93affbab3

112121111100083 has 2 divisors, whose sum is σ = 112121111100084. Its totient is φ = 112121111100082.

The previous prime is 112121111100079. The next prime is 112121111100091. The reversal of 112121111100083 is 380001111121211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 112121111100083 - 22 = 112121111100079 is a prime.

It is a super-2 number, since 2×1121211111000832 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112121111100023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060555550041 + 56060555550042.

It is an arithmetic number, because the mean of its divisors is an integer number (56060555550042).

Almost surely, 2112121111100083 is an apocalyptic number.

112121111100083 is a deficient number, since it is larger than the sum of its proper divisors (1).

112121111100083 is an equidigital number, since it uses as much as digits as its factorization.

112121111100083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 23.

Adding to 112121111100083 its reverse (380001111121211), we get a palindrome (492122222221294).

The spelling of 112121111100083 in words is "one hundred twelve trillion, one hundred twenty-one billion, one hundred eleven million, one hundred thousand, eighty-three".