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112121122022317 is a prime number
BaseRepresentation
bin11001011111100100111011…
…101001100110001110101101
3112200222200012202211212211201
4121133210323221212032231
5104143443024214203232
61034243422110045501
732421324632314252
oct3137447351461655
9480880182755751
10112121122022317
11327a8334432071
12106a99a8aa9891
134a73c90311605
141d98996b69429
15ce67dae2bbe7
hex65f93ba663ad

112121122022317 has 2 divisors, whose sum is σ = 112121122022318. Its totient is φ = 112121122022316.

The previous prime is 112121122022309. The next prime is 112121122022383. The reversal of 112121122022317 is 713220221121211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84284407867716 + 27836714154601 = 9180654^2 + 5276051^2 .

It is a cyclic number.

It is not a de Polignac number, because 112121122022317 - 23 = 112121122022309 is a prime.

It is a super-2 number, since 2×1121211220223172 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112121122028317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060561011158 + 56060561011159.

It is an arithmetic number, because the mean of its divisors is an integer number (56060561011159).

Almost surely, 2112121122022317 is an apocalyptic number.

It is an amenable number.

112121122022317 is a deficient number, since it is larger than the sum of its proper divisors (1).

112121122022317 is an equidigital number, since it uses as much as digits as its factorization.

112121122022317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 28.

Adding to 112121122022317 its reverse (713220221121211), we get a palindrome (825341343143528).

The spelling of 112121122022317 in words is "one hundred twelve trillion, one hundred twenty-one billion, one hundred twenty-two million, twenty-two thousand, three hundred seventeen".